/[MITgcm]/manual/s_algorithm/text/time_stepping.tex
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revision 1.22 by jmc, Tue Jun 27 19:10:32 2006 UTC revision 1.23 by edhill, Tue Jun 27 22:29:56 2006 UTC
# Line 609  G_{\theta,S}^{(n+1/2)} & = & (3/2+\epsil Line 609  G_{\theta,S}^{(n+1/2)} & = & (3/2+\epsil
609  (\theta^*,S^*) & = & (\theta^{n},S^{n}) + \Delta t G_{\theta,S}^{(n+1/2)}  (\theta^*,S^*) & = & (\theta^{n},S^{n}) + \Delta t G_{\theta,S}^{(n+1/2)}
610  \label{eq:tstar-staggered} \\  \label{eq:tstar-staggered} \\
611  (\theta^{n+1},S^{n+1}) & = & {\cal L}^{-1}_{\theta,S} (\theta^*,S^*)  (\theta^{n+1},S^{n+1}) & = & {\cal L}^{-1}_{\theta,S} (\theta^*,S^*)
612  \label{eq:t-n+1-staggered} \\  \label{eq:t-n+1-staggered}
613  \end{eqnarray}  \end{eqnarray}
614  The corresponding calling tree is given in  The corresponding calling tree is given in
615  \ref{fig:call-tree-adams-bashforth-staggered}.  \ref{fig:call-tree-adams-bashforth-staggered}.
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