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% date = dtecco2(X,FORM) |
2 |
% |
3 |
% If: |
4 |
% FORM = 0, translate the stepnum X into a date string (yyyymmddHHMM) |
5 |
% FORM = 1, translate the date string X (yyyymmddHHMM) into a stepnum |
6 |
% |
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% 06/08/29 |
8 |
% gmaze@mit.edu |
9 |
% |
10 |
|
11 |
function varargout = dtecco2(varargin) |
12 |
|
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% Test inputs: |
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if nargin ~= 2 |
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help dtecco2.m |
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error('dtecco2.m : Wrong number of parameters'); |
17 |
return |
18 |
end %if |
19 |
|
20 |
% Recup inputs: |
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X = varargin{1}; |
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FORM = varargin{2}; |
23 |
|
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% New tests: |
25 |
if FORM~=0 & FORM~=1 |
26 |
help dtecco2.m |
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error('dtecco2.m : Second argument must be 0 or 1'); |
28 |
return |
29 |
elseif FORM == 0 & ~isnumeric(X) |
30 |
help dtecco2.m |
31 |
error('dtecco2.m : if 2nd arg is 0, 1st arg must be numeric'); |
32 |
return |
33 |
elseif FORM == 1 & isnumeric(X) |
34 |
help dtecco2.m |
35 |
error('dtecco2.m : if 2nd arg is 1, 1st arg must be a string'); |
36 |
return |
37 |
end |
38 |
|
39 |
|
40 |
% Let's go: |
41 |
switch FORM |
42 |
|
43 |
case 0 |
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ID = datestr(datenum(1992,1,1)+X*300/60/60/24,'yyyymmddHHMM'); |
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varargout(1) = {ID}; |
46 |
|
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case 1 |
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ID = 60*60*24/300*( datenum(X,'yyyymmddHHMM') - datenum(1992,1,1) ); |
49 |
varargout(1) = {ID}; |
50 |
|
51 |
|
52 |
end %switch |