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gmaze |
1.1 |
% date = dtecco2(X,FORM) |
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% |
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% If: |
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% FORM = 0, translate the stepnum X into a date string (yyyymmddHHMM) |
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% FORM = 1, translate the date string X (yyyymmddHHMM) into a stepnum |
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% |
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% 06/08/29 |
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% gmaze@mit.edu |
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% |
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function varargout = dtecco2(varargin) |
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% Test inputs: |
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if nargin ~= 2 |
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help dtecco2.m |
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error('dtecco2.m : Wrong number of parameters'); |
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return |
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end %if |
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% Recup inputs: |
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X = varargin{1}; |
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FORM = varargin{2}; |
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% New tests: |
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if FORM~=0 & FORM~=1 |
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help dtecco2.m |
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error('dtecco2.m : Second argument must be 0 or 1'); |
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return |
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elseif FORM == 0 & ~isnumeric(X) |
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help dtecco2.m |
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error('dtecco2.m : if 2nd arg is 0, 1st arg must be numeric'); |
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return |
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elseif FORM == 1 & isnumeric(X) |
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help dtecco2.m |
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error('dtecco2.m : if 2nd arg is 1, 1st arg must be a string'); |
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return |
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end |
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% Let's go: |
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switch FORM |
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case 0 |
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ID = datestr(datenum(1992,1,1)+X*300/60/60/24,'yyyymmddHHMM'); |
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varargout(1) = {ID}; |
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case 1 |
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ID = 60*60*24/300*( datenum(X,'yyyymmddHHMM') - datenum(1992,1,1) ); |
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varargout(1) = {ID}; |
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end %switch |