| 147 |
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|
| 148 |
When we include the nitrogen as a potential limiting nutrient (EXP2) we |
When we include the nitrogen as a potential limiting nutrient (EXP2) we |
| 149 |
modify $N_i^{lim}$ to take into account the uptake inhibition caused by ammonium: |
modify $N_i^{lim}$ to take into account the uptake inhibition caused by ammonium: |
| 150 |
\[ |
\begin{align*} |
| 151 |
N_N^{lim} = \frac{NO_3 + NO_2}{NO_3+NO_2+\kappa_{IN}} e^{-\psi NH_4} |
N_N^{lim} &= \frac{NO_2}{NO_2+\kappa_{IN}} e^{-\psi NH_4} |
| 152 |
+\frac{NH_4}{NH_4 + \kappa_{NH4}} |
+\frac{NH_4}{NH_4 + \kappa_{NH4}} && \text{(nsource=1)} \\ |
| 153 |
\] |
N_N^{lim} &= \frac{NH_4}{NH_4 + \kappa_{NH4}} && \text{(nsource=2)} \\ |
| 154 |
|
N_N^{lim} &= \frac{NO_3 + NO_2}{NO_3+NO_2+\kappa_{IN}} e^{-\psi NH_4} |
| 155 |
|
+\frac{NH_4}{NH_4 + \kappa_{NH4}} && \text{(nsource=3)} |
| 156 |
|
\end{align*} |
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where $\psi$ reflects the inhibition and $\kappa_{IN}$ and $ \kappa_{NH4}$ |
where $\psi$ reflects the inhibition and $\kappa_{IN}$ and $ \kappa_{NH4}$ |
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are the half saturation constant of $IN=NO_3+NO_2$ and $NH_4$ respectively. |
are the half saturation constant of $IN=NO_3+NO_2$ and $NH_4$ respectively. |
| 159 |
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