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C $Header: /u/gcmpack/MITgcm/pkg/cal/cal_daysformonth.F,v 1.2 2003/10/09 04:19:19 edhill Exp $ |
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C $Name: $ |
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|
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#include "CAL_OPTIONS.h" |
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|
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subroutine cal_DaysForMonth( |
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I imonth, |
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O firstday, |
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O lastday, |
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O ndays, |
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I mythid |
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& ) |
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|
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c ================================================================== |
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c SUBROUTINE cal_DaysForMonth |
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c ================================================================== |
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c |
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c o Given the current month of the integration this routine returns |
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c first, the last and the number of calendar days that will have |
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c to be performed. |
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c |
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c This routine also checks consistency of variables quite |
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c extensively. |
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c |
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c started: Christian Eckert eckert@mit.edu 06-Apr-2000 |
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c |
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c changed: |
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c |
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c ================================================================== |
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c SUBROUTINE cal_DaysForMonth |
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c ================================================================== |
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|
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implicit none |
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|
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c == global variables == |
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|
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#include "cal.h" |
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|
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c == routine arguments == |
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|
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integer imonth |
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integer firstday |
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integer lastday |
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integer ndays |
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integer mythid |
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|
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c == local variables == |
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|
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integer i |
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integer ierr |
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integer nummonths |
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integer numdays |
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integer firstyear |
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integer firstmonth |
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integer firstd |
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integer lyfirst |
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integer lastyear |
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integer lastmonth |
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integer lastd |
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integer lastsecs |
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integer lylast |
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integer currentyear |
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integer currentmonth |
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integer lycurrent |
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|
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c == external == |
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|
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integer cal_IntMonths |
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external cal_IntMonths |
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integer cal_IsLeap |
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external cal_IsLeap |
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|
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c == end of interface == |
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|
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lyfirst = cal_IsLeap( firstyear, mythid ) |
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lylast = cal_IsLeap( lastyear, mythid ) |
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|
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nummonths = cal_Intmonths( mythid ) |
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|
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firstyear = modelstartdate(1)/10000 |
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firstmonth = mod(modelstartdate(1)/100,100) |
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firstd = mod(modelstartdate(1),100) |
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lastyear = modelenddate(1)/10000 |
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lastmonth = mod(modelenddate(1)/100,100) |
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lastd = mod(modelenddate(1),100) |
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lastsecs = modelenddate(2)/10000*secondsperhour + |
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& mod(modelenddate(2)/100,100)*secondsperminute + |
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& mod(modelenddate(2),100) |
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|
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if ( nummonths .eq. 1 ) then |
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if ( imonth .eq. 1 ) then |
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c-- Get the number of days in the first month. |
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if ( firstmonth .eq. lastmonth ) then |
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if (lastsecs .eq. 0) then |
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c-- Not really another day. |
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lastday = lastd - 1 |
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else |
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lastday = lastd |
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endif |
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firstday = 1 |
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else if ( mod(firstmonth+1,nmonthyear) .eq. lastmonth ) then |
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c-- This can only happen if we end at midnight of the first |
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c-- day of the next month. |
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if ( ( modelenddate(2) .eq. 0 ) .and. |
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& ( mod(modelenddate(1),100) .eq. 1 ) ) then |
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firstday = firstd |
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lastday = ndaymonth(firstmonth,lyfirst) |
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else |
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c-- We do not end at midnight of the first day of |
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c-- the next month. |
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ierr = 2704 |
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call cal_PrintError( ierr, mythid ) |
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stop ' stopped in cal_DaysForMonth.' |
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endif |
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else |
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c-- The first and the last month are inconsistent with imonth. |
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ierr = 2703 |
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call cal_PrintError( ierr, mythid ) |
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stop ' stopped in cal_DaysForMonth.' |
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endif |
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else |
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c-- The variables nummonths and imonth are inconsistent; |
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c-- ( imonth .gt. nummonths ). |
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ierr = 2702 |
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call cal_PrintError( ierr, mythid ) |
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stop ' stopped in cal_DaysForMonth.' |
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endif |
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|
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else if ( nummonths .gt. 1 ) then |
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c-- More than one month of integration. |
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if ( imonth .eq. 1 ) then |
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firstday = 1 |
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lastday = ndaymonth(firstmonth,lyfirst) - firstd + 1 |
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else if ( ( imonth .gt. 1 ) .and. |
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& ( imonth .lt. nummonths ) ) then |
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c-- Somewhere between first and last month. |
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currentmonth = firstmonth |
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currentyear = firstyear |
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numdays = ndaymonth(firstmonth,lyfirst) - firstd + 1 |
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do i = 2,imonth-1 |
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c-- Accumulate days of the intermediate months. |
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currentmonth = mod(currentmonth+1,nmonthyear) |
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if ( currentmonth .eq. 0 ) then |
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currentmonth = 12 |
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endif |
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if ( currentmonth .eq. 1 ) then |
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currentyear = currentyear + 1 |
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endif |
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lycurrent = cal_IsLeap( currentyear, mythid ) |
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numdays = numdays + ndaymonth(currentmonth,lycurrent) |
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enddo |
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currentmonth = mod(currentmonth+1,nmonthyear) |
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if ( currentmonth .eq. 0 ) then |
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currentmonth = 12 |
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endif |
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if ( currentmonth .eq. 1 ) then |
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currentyear = currentyear + 1 |
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endif |
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lycurrent = cal_IsLeap( currentyear, mythid ) |
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firstday = numdays + 1 |
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lastday = numdays + ndaymonth(currentmonth,lycurrent) |
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else if ( imonth .eq. nummonths ) then |
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c-- The last month of the integration. |
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currentmonth = firstmonth |
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currentyear = firstyear |
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numdays = ndaymonth(firstmonth,lyfirst) - firstd + 1 |
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do i = 2,nummonths-1 |
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c-- Accumulate days of the intermediate months. |
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currentmonth = mod(currentmonth+1,nmonthyear) |
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if ( currentmonth .eq. 0 ) then |
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currentmonth = 12 |
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endif |
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if ( currentmonth .eq. 1 ) then |
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currentyear = currentyear + 1 |
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endif |
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lycurrent = cal_IsLeap( currentyear, mythid ) |
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numdays = numdays + ndaymonth(currentmonth,lycurrent) |
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enddo |
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c-- Prepare for the last month of integration. |
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currentmonth = mod(currentmonth+1,nmonthyear) |
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if ( currentmonth .eq. 0 ) then |
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currentmonth = 12 |
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endif |
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if ( currentmonth .eq. 1 ) then |
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currentyear = currentyear + 1 |
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endif |
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lycurrent = cal_IsLeap( currentyear, mythid ) |
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if ( ( modelenddate(2) .eq. 0 ) .and. |
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& ( mod(modelenddate(1),100) .eq. 1 ) ) then |
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c-- This can only happen if we end at midnight of the first |
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c-- day of the next month. |
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lastday = numdays + ndaymonth(currentmonth,lycurrent) |
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else |
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c-- We do not stop at midnight of the first day of the |
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c-- next month. |
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if (lastsecs .eq. 0) then |
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c-- But we might stop at midnight of a day. |
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lastday = numdays + lastd - 1 |
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else |
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lastday = numdays + lastd |
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endif |
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endif |
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firstday = numdays + 1 |
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else |
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c-- The variables imonth and nummonths are inconsistent. |
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ierr = 2705 |
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call cal_PrintError( ierr, mythid ) |
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stop ' stopped in cal_DaysForMonth.' |
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endif |
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else |
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c-- The number of months to integrate is wrong; check cal_IntMonths. |
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ierr = 2701 |
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call cal_PrintError( ierr, mythid ) |
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stop ' stopped in cal_DaysForMonth.' |
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endif |
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c-- The number of days to integrate in the given month. |
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ndays = lastday - firstday + 1 |
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|
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return |
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end |
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