| 16 |
C \==========================================================/ |
C \==========================================================/ |
| 17 |
IMPLICIT NONE |
IMPLICIT NONE |
| 18 |
C Returns TRUE if val1 and val2 are different multiples of freq. |
C Returns TRUE if val1 and val2 are different multiples of freq. |
| 19 |
REAL freq, val1, val2 |
_RL freq, val1, val2 |
| 20 |
CEndofinterface |
CEndofinterface |
| 21 |
|
_RL f, v1, v2, v3, v4, d1, d2, d3, step |
| 22 |
|
|
| 23 |
|
C o Do easy cases first. |
| 24 |
DIFFERENT_MULTIPLE = .FALSE. |
DIFFERENT_MULTIPLE = .FALSE. |
| 25 |
IF ( freq .EQ. 0. ) THEN |
IF ( freq .EQ. 0. ) RETURN |
| 26 |
DIFFERENT_MULTIPLE = .FALSE. |
IF ( ABS(val1-val2) .GT. freq ) THEN |
| 27 |
ELSE |
DIFFERENT_MULTIPLE = .TRUE. |
| 28 |
DIFFERENT_MULTIPLE = INT(val1/freq) .NE. INT(val2/freq) |
RETURN |
| 29 |
ENDIF |
ENDIF |
|
END |
|
| 30 |
|
|
| 31 |
|
C o This case is more complex because of round-off error |
| 32 |
|
f = freq |
| 33 |
|
v1 = val1 |
| 34 |
|
v2 = val2 |
| 35 |
|
step = v1-v2 |
| 36 |
|
|
| 37 |
|
C Test v1 to see if its a "closest multiple" |
| 38 |
|
v3 = v1 + step |
| 39 |
|
v4 = NINT(v1/f)*f |
| 40 |
|
d1 = v1-v4 |
| 41 |
|
d2 = v2-v4 |
| 42 |
|
d3 = v3-v4 |
| 43 |
|
IF ( ABS(d1) .LE. ABS(d2) .AND. |
| 44 |
|
& ABS(d1) .LE. ABS(d3) ) DIFFERENT_MULTIPLE = .TRUE. |
| 45 |
|
|
| 46 |
|
END |